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soldi70 [24.7K]
3 years ago
7

Find the value of x in the triangle shown below.1612​

Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

There is no picture shown

So sorry but there is no picture with the question

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Phil and rory both like to play golf . Decided to see how far they can hit a golf ball. Phil can hit the golf ball 72 yards. Ror
Varvara68 [4.7K]

Answer:

48 yards

Step-by-step explanation:

72-24= 48

3 0
3 years ago
A point lies in quadrant 2. If it is rotated 180 degrees counterclockwise, which quadrant will the point come to rest?
NeTakaya
A point (a, b) in the second Quadrant, is any point where a is negative and b is positive.

For example (-3, 5), (-189, 14) etc are all points in the 2.Quadrant

Rotating a point P(x, y) in the second Quadrant 180° counterclockwise, means rotating 180° counterclockwise about the origin, which maps point P to P'(-a, -b) in the fourth Quadrant.

3 0
3 years ago
Evan went to the park and saw four animals.
dsp73

Answer:

He saw <u>1 duck</u> and <u>3 dogs</u>.

Step-by-step explanation:

Given:

Evan went to the park and saw four animals.

Each animal was either a duck or a dog.

He saw a total of 14 legs.

Now, to find the number of each animal he had seen.

Let the number of duck be x.

And the number of dog be y.

So, total number of animals:

x+y=4\\y=4-x

Now, the total number of legs he did see:

<em>As we know the legs of a duck are 2 and a dog are 4.</em>

2x+4y=14\\2x+4(4-x)=14\\2x+16-4x=14\\-2x+16=14

Adding both sides by -16 we get:

-2x=-2

Dividing both sides by -2 we get:

x=1

The number of duck = 1.

Now, putting the value of x in above equation we get:

y=4-x

y=4-1\\y=3.

The number of dogs = 3.

Therefore, he saw 1 duck and 3 dogs.

4 0
3 years ago
What is 6x10 to the negative third power
kakasveta [241]

60 to the negative 3 power

3 0
4 years ago
Compute and compare the side lengths of the two figures. Does this support an argument claiming that they are congruent? What el
Sunny_sXe [5.5K]
We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].

AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13

BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13

CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13

DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13

The two polygons are squares with the same side lengths. 

But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions: 
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.

The third condition was not proven.
6 0
3 years ago
Read 2 more answers
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