Answer:
![P(x \le 21) = 0.69146](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29%20%3D%200.69146)
Step-by-step explanation:
The missing parameters are:
--- population
--- population mean
-- population standard deviation
Required
![P(x \le 21)](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29)
First, calculate the sample standard deviation
![\sigma_x = \frac{\sigma}{\sqrt n}](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%20n%7D)
![\sigma_x = \frac{16}{\sqrt {64}}](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%20%5Cfrac%7B16%7D%7B%5Csqrt%20%7B64%7D%7D)
![\sigma_x = \frac{16}{8}](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%20%5Cfrac%7B16%7D%7B8%7D)
![\sigma_x = 2](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%202)
Next, calculate the sample mean ![\bar_x](https://tex.z-dn.net/?f=%5Cbar_x)
![\bar x = \mu](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cmu)
So:
![\bar x = 20](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2020)
So, we have:
![\sigma_x = 2](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%202)
![\bar x = 20](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2020)
![x = 21](https://tex.z-dn.net/?f=x%20%3D%2021)
Calculate the z score
![x = \frac{x - \mu}{\sigma}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7Bx%20-%20%5Cmu%7D%7B%5Csigma%7D)
![x = \frac{21 - 20}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B21%20-%2020%7D%7B2%7D)
![x = \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
![x = 0.50](https://tex.z-dn.net/?f=x%20%3D%200.50)
So, we have:
![P(x \le 21) = P(z \le 0.50)](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29%20%3D%20P%28z%20%5Cle%200.50%29)
From the z table
![P(z \le 0.50) = 0.69146](https://tex.z-dn.net/?f=P%28z%20%5Cle%200.50%29%20%3D%200.69146)
So:
![P(x \le 21) = 0.69146](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29%20%3D%200.69146)
Simplified it's 576x^8y^7
Answer:
<h2>√126</h2>
Option D is the right option.
solution,
![\frac{ac}{bc} = \frac{bc}{dc} \\ or \: \frac{18}{ m} = \frac{m}{7} \\ or \: m \times \: m = 18 \times 7(cross \: multiplication) \\ or \: {m}^{2} = 126 \\ m = \sqrt{126}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bac%7D%7Bbc%7D%20%20%3D%20%20%5Cfrac%7Bbc%7D%7Bdc%7D%20%20%5C%5C%20or%20%5C%3A%20%20%5Cfrac%7B18%7D%7B%20m%7D%20%20%3D%20%20%5Cfrac%7Bm%7D%7B7%7D%20%20%5C%5C%20or%20%5C%3A%20m%20%5Ctimes%20%5C%3A%20m%20%3D%2018%20%5Ctimes%207%28cross%20%5C%3A%20multiplication%29%20%5C%5C%20or%20%5C%3A%20%20%7Bm%7D%5E%7B2%7D%20%20%3D%20126%20%5C%5C%20m%20%3D%20%20%5Csqrt%7B126%7D%20)
Hope this helps..
Good luck on your assignment.
Hope