Ask question

Ask question

All categories

My name is Ann [436]

2 years ago

13

In which quadrant of the coordinate plane will the ordered pair (2,-3)

1 answer:

Natalka [10]2 years ago

4 0

The quadrant of the coordinate plane (2,-3) Will be located in is quadrant IV (4)

You might be interested in

Which operation involving complex numbers requires the use of a conjugate to be carried out?

Pani-rosa [81]

Answer:

The correct answer will be "Division".

Step-by-step explanation:

The procedure represents numerous values requiring something like a conjugate to have been done becomes division, since the denominator conjugate multiplies the numeric values including its quotient to represent the quotient of several complex numbers throughout the standard language.
It is indeed a method used to separate a set of items across equal proportions.

3 0

2 years ago

I need to solve the equation for z

Greeley [361]

I think this is how you do it...

7 0

3 years ago

Read 2 more answers

The amount of bacteria in a fish tank was 830. After 5 hours, the amount of bacteria is 3202.

alina1380 [7]

Answer: 37.92

Step-by-step explanation: We know that 3202 / 5 = 640.4.

We subtract that by 830 to get (830 - 640.4 =) 189.6. Then we do / by five again to get 37.92. That is the answer.

3 0

1 year ago

4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean

Ede4ka [16]

Adding 2 to each value of the random variable $X$ makes a new random variable $X+2$ . Its mean would be

$E[X+2]=E[X]+E[2]=E[X]+2$

since expectation is linear, and the expected value of a constant is that constant. $E[X]$ is the mean of $X$ , so the new mean would be

$E[X+2]=10+2=12$

The variance of a random variable $X$ is

$V[X]=E[X^2]-E[X]^2$

so the variance of $X+2$ would be

$V[X+2]=E[(X+2)^2]-E[X+2]^2$

We already know $E[X+2]=12$ , so simplifying above, we get

$V[X+2]=E[X^2+4X+4]-12^2$

$V[X+2]=E[X^2]+4E[X]+4-12^2$

$V[X+2]=(V[X]+E[X]^2)+4E[X]-140$

Standard deviation is the square root of variance, so $V[X]=3^2=9$ .

$\implies V[X+2]=(9+10^2)+4(10)-140=9$

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of $aX+b$ for $a,b\in\mathbb R$ is

$V[aX+b]=a^2V[X]+b^2V[1]$

but the variance of a constant is 0. In this case, $a=1$ , so we're left with $V[X+2]=V[X]$ , as expected.

5 0

3 years ago

Which is an x-intercept of the graphed function?<br> O(0, 4)<br> 0 (-1.0)<br> Q (40)<br> (0,-1)

NISA [10]

Answer:idk just here for the points

Step-by-step explanation:

6 2

2 years ago

Read 3 more answers