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Harlamova29_29 [7]

3 years ago

6

Three times Mary's age added to Beth's age is 34 years. Half of Mary's age minus Beth's age is 1 year. How old are Mary and Beth

?

1 answer:

Evgen [1.6K]3 years ago

7 0

Answer:

It’s 15 and 17

Step-by-step explanation:

34-7x=2y

-13 -13

(15,17)

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Salma, joe, and alan sent a total of 106 text messages during the weekend, salma sent 9 fewer messages than alan. Joe sent 3 tim

krek1111 [17]

Answer:

Salma, joe, and alan sent 14, 69, and 23 text messages respectively

Step-by-step explanation:

Given that Salma, joe, and alan sent a total of 106 text messages during the weekend, it means that

s + j + a = 106 where s, j, and a are the number of messages sent by Salma, joe, and alan respectively

Given salma sent 9 fewer messages than alan

s = a - 9

Joe sent 3 times as many messages as alan

j = 3a

hence

a - 9 + 3a + a = 106

5a - 9 = 106

5a = 106 + 9

5a = 115

Divide both sides by 5

a = 115/5

= 23

s = 23 - 9

= 14

j = 3* 23

= 69

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3 years ago

Which graph represents the equation Cost = Number of toppings x 2 + 3

Svetllana [295]

Answer:

the third graph

Step-by-step explanation:

its the only one that has a y intercept of 3 and if you plug in each of the values of x it is correct

5 0

3 years ago

In answering on a multiple choice test, a student either know the answer or guesses. Let p be the probability that the students

LenaWriter [7]

Answer:

$P(A_{1}|B ) =\frac{mp}{1+p(m-1)}$

Step-by-step explanation:

For mutually exclusive events as A1, A2, A3, etc, Bayes' theorem states:

$P(A|B)= \frac{P(B|A)P(A)}{P(B)}$

P(A|B) is a conditional probability: the likelihood of event A occurring given that B is true.

P(B|A) is a conditional probability: the likelihood of event B occurring given that A is true.

P(A) is the probability that A occurs

P(B) is the probability that B occurs

For this problem:

A1 is the probability that the student knows the answer

A2 is the probability that the student guesses the answer

B is the probability that the student answer correctly

$P(A_{1})=p \\P(A_{2})=1-p \\P(B|A_{1})=1 \\P(B|A_{2})=\frac{1}{m} \\P(B)= P(A_{1})P(B|A_{1}) + P(A_{2})P(B|A_{2})= p+\frac{1-p}{m} \\$

P(B|A₁) means the probability that the answer is correct when he knew the answer

P(B|A₂) means the probability that the answer is correct when he guessed the answer

P(A₁|B) means the probability that he knew the answer when the answer was correct

Replacing everything in the Bayes' theorem you get:

$P(A_{1}|B)= \frac{P(B|A_{1})P(A_{1})}{P(B)}=\frac{(1)(p)}{p+\frac{1-p}{m}} =\frac{mp}{mp+1-p} =\frac{mp}{1+p(m-1)}$

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