AB = 9 cm
BC = 6cm
CD = 7 cm
AE = 6 cm
3BC = AB
3ED = AE
AB = AE
BC ED
⁹/₃ = ⁶/ₓ
3 · 6 = 9 · x
18 = 9x
9 9
2 = x
ED = 2 cm
Given:
A figure in which a transversal line t intersect the two parallel lines a and b.
To find:
The measure of the numbered angles.
Solution:
If a transversal line intersect the two parallel lines, then
1. Corresponding angles are equal.
2. Alternate interior angles are equal.
3. Alternate exterior angles are equal.
Now,
(Linear pair)
(Vertically opposite angles)
(Vertically opposite angles)
(Corresponding angles)
(Alternate interior angles)
(Alternate exterior angles)
(Corresponding angles)
Therefore, 
.
Answer:
If rounded to the nearest 10 bacteria, then it would be 500 bacteria.
Step-by-step explanation:
First multiply 150 by two in order to get 300, that leaves 4 hours to figure out. From there you can figure out the rest by seeing that 4 is 2/3 of 6. I converted it into the decimal number .66. Multiply 300 by .66 to get 198 and then add it to 300 to get 498. Then just round it up to the nearest 10 bacteria which leaves you with the final answer of 500 bacteria.
Answer:
90 in²
Step-by-step explanation:
The figure's area is that of four right triangles, each with legs of 6 in and 7.5 in. The area of each triangle is half the product of the leg lengths, so is ...
triangle area = (1/2)(6 in)(7.5 in)
Then the area of 4 of those triangles is ...
figure area = 4 · triangle area = 2(6 in)(7.5 in) = 90 in²
Both are 1/2 because there is two sides so half the time it would be heads and half would be tails
