The solution for this problem is:It's given that the heights are normally distributed.
5 feet 7 inches = (5*12 +7) inches = (60+7) inches = 67 inches.
The z-score is (67 - 69.1)/(2.65) = -1.136. The probability is 0.127978 or 12.8%, making probability of a height over 67 inches
Answer:
x = 18
Step-by-step explanation:
(whole secant) x (external part) = (whole secant) x (external part)
(6+x)6 = (8+10)* 8
6*(6+x) = 8(18)
Divide each side by 6
6+x = 8(18)/6
6+x = 8*3
6+x = 24
Subtract 6 from each side
6+x-6 =24-6
x = 18
Step-by-step explanation:
f(x) = y = -1/2 × sqrt(x + 3), x >= -3
-2y = sqrt(x + 3)
4y² = x + 3
x = 4y² - 3
and now we need to rename x to y and y to x to make it a "normal" function :
y = 4x² - 3
since in the original function x >= -3, this gave us y <=0.
and therefore (remember the x of the inverse function actually stands for the y of the original function) the limit for the inverse function is x <= 0.
so, again, the full answer is
f^-1(x) = 4x² - 3, x <= 0
Trigonometry would help with this question.
The area of a regular hexagon is ((3√3)s^2)/2 where s is the side.
Plugging in 2 gives us 6√3 or 10.39 feet.
