Write a function that is passed in a positive integer, n, and sum up all the digits from 1 to n, doubling the even numbers. In o
1 answer:
Answer:
Written in Python
def sums(n):
total = 0
for i in range(1,n+1):
if i%2 == 0:
total = total + i*2
else:
total = total + i
return(total)
Step-by-step explanation:
The function is written in Python
def sums(n):
This initializes total to 0
total = 0
This iterates through the integers that makes up n i.e. 1,2,3.....n
for i in range(1,n+1):
This checks if current digit is even
if i%2 == 0:
If yes, it adds the double of the digit
total = total + i*2
else:
If otherwise, it adds the digit
total = total + i
This prints the calculated sum or total
return(total)
To call the function from main, use the following:
print(sums(n))
Where n is a positive integer. i.e.
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