Answer:
Interactive voice response
Explanation:
Interactive voice response (IVR) is a technological innovation which allows computer systems to interact with individuals with the use of voice and Dual-tone multi-frequency signaling (DTMF) tones input through a keypad. In telecommunications sector, IVR enables customers to interact with a company’s host system through the use of a telephone keypad or by using speech recognition, after which services can be accessed by the use of the IVR dialogue.
Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
Answer:
The answer is Letter D. Dumpster diving.
Explanation:
This process of going through a target's trash is known in the community as dumpster diving. This attack is a technique used to retrieve information that could be used to carry out an attack on a computer network.
It is important to inform that the dumpster diving it is not limited to searching through the trash for obvious treasures like acess codes or passwords written down on sticky notes.
Answer:
// This program is written in C++
// Comments are used for explanatory purpose
// Program starts here
#include<iostream.h>
#include<stdlib.h>
int main()
{
// Declare variables
int num, selectno;
string status;
randomize();
//Generate random number;
num=rand()%10000;
// Prompt to guess a number
cout<<"You have only 10 tries\nTake a guess: ";
int tries = 0;
while (tries != 10)
{
cin>>selectno;
if(selectno == num){
cout<<"You passed at the "<<count+1<<" attempt";
tries = 10;
}
else
{
cout<<"You failed. Take another guess\n You have "<<10 - count + 1 <<" attempts";
}
tries++;
if(tries >= 10)
{
break;
}
}
return 0;
}
