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Andrews [41]
3 years ago
12

Solve: |x−6|+7≥−1. Write your solution in interval notation.

Mathematics
1 answer:
hammer [34]3 years ago
5 0

Answer:

-2 ≤ x ≤ 14

Step-by-step explanation:

x - 6 + 7 ≥ -1

x + 1 ≥ -1

x ≥ -2

-(x - 6) + 7 ≥ -1

-x + 6 + 7 ≥ -1

-x + 13 ≥ -1

-x ≥ -14

x ≤ 14

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What is the equation, in factored form, of the quadratic functions shown in the graph?
mina [271]

Answer:

(x+3)(x-2)

Step-by-step explanation:

We can immediately see that there are roots at x = -3, and x = 2.

Because the website gives us that this in the form of (x + _) (x - _), our anwser is (x+3)(x-2)

oops I just saw your comment. Too late i guess...

7 0
3 years ago
Through (1,-6) parallel to the line x + 2y = 6
MakcuM [25]

Hello!

To find the line parallel to the line x + 2y = 6 and passing through the point (1, -6), we will need to know that if two lines are parallel, then their slopes are equivalent to each other.

Since the given equation is written in standard form, we will need to change it to slope-intercept form to get the slope. Slope-intercept form is: y = mx + b.

x + 2y = 6 (subtract x from both sides)

2y = 6 - x (divide both sides by 2)

y = 6/2 - x/2

y = -1/2x + 3 | The slope of parallel lines are -1/2.

Since we are given the slope, we need to find the y-intercept of the line that goes through the point (1, -6) by substituting that point into a new equation with a slope of m equalling to -1/2.

y = -1/2x + b (substitute the given point)

-6 = -1/2(1) + b (simplify - multiply)

-6 = -1/2 + b (add 1/2 to both sides)

b = -11/2 | The y-intercept of the parallel line is -13/2.

Therefore, the line parallel to x + 2y = 6 and goes through the ordered pair (1, -6) is y = -1/2x + -11/2.

8 0
3 years ago
How to show work 1200 divided by three
anygoal [31]
1200 ÷ 3 = 400 ⇒  400 × 3= 1200 so the answer is right  :))
i hope this be helpful 
have a nice day 
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il63 [147K]

Answer:

495 min

Step-by-step explanation:

4 0
3 years ago
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The number -13 can be classified as:
pogonyaev
<h3>Answer: Choice B) real and integer</h3>

Explanation:

The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} basically its the set of positive and negative whole numbers, including 0 as well. The set of whole numbers is {0, 1, 2, 3, 4, ...} so any positive number that does not a fractional or decimal part. The value 0 is included in the set of whole numbers. The natural numbers is {1, 2, 3, 4, ...} so it is the set of whole numbers but we kicked out 0 from this set. The set of natural numbers is also called the set of counting numbers.

If we take any two integers and divide them then you'll get a rational number. You cannot have zero in the denominator, but you can have any other integer. For example,  2 and 3 divide to get the fraction 2/3 which is a rational number. Numbers that we cannot express as a fraction of two integers are said to be irrational. An example of this is pi = 3.14 which is irrational. We cannot write pi as a ratio of two integers. One approximation is pi = 22/7, but this doesn't represent pi exactly. Any integer itself is rational. Something like -13 can be written as -13/1, so we cannot say -13 is irrational. That rules out choice A. Choice C is ruled out because negative numbers aren't natural numbers. The same can be said about -13 not being part of the whole number set {0, 1, 2, 3, 4, ...} so choice D is also false.

7 0
3 years ago
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