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3 years ago

PLZ!!!

Mathematics

2 answers:

Len [333]3 years ago

5 0

Answer:

Step-by-step explanation:

count each dot

Nimfa-mama [501]3 years ago

4 0

The answer is 16 all you have to do is count all the dots

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Check picture if u kno geometry

Scorpion4ik [409]

Answer:

141.5 in

Step-by-step explanation

AB // CD // EF

12 / 15 = 21 / y (By the property of 3 parallel lines and its transversals)

y = (15*21) / 12 = 26.25

CD // EF // GH

21 / y = x / 10 21 / 26.25 = x / 10

x = (21*10) / 26.25

x = 8

perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5

4 0

3 years ago

janis and susan went to a clearance sale at a clothing store all blouses were selling for the same price and all skirts were sel

alexandr402 [8]

$8.5, $\frac{68}{8} = 8.5$

5 0

3 years ago

MATH MATh MAtH MAAAAThHhH YAAA

MariettaO [177]

Answer:

6k + 19

Step-by-step explanation:

7k - k + 19

6k + 19

7 0

3 years ago

Read 2 more answers

Factor x3 – 7x2 – 5x + 35 by grouping. What is the resulting expression?

Afina-wow [57]

Answer:

3rd option

Step-by-step explanation:

Given

x³ - 7x² - 5x + 35 ( factor the first/second and third/fourt terms )

= x² (x - 7) - 5(x - 7) ← factor out (x - 7) from each term

= (x² - 5)(x - 7)

5 0

3 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus

5 0

4 years ago