If f(x) = x^3 + 13x^2 + 46 x + 48 and x + 8 is a factor of f(x) find all of the zeroes of f(x) algebraically

Mathematics

1 answer:

Korolek [52]3 years ago

8 0

If x + 8 is a factor, we can factor it out from f(x).

f(x) = (x+8)(x²+5x+6)

= (x+8)(x+2)(x+3)

The zeroes of f(x) are -8, -2 and -3.

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The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

x-intercept = -4, -2 and 2
y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

Increasing interval: (0.5, ∝) and (-∝, -3)
Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

Positive interval: (-4, -2) and (2, ∝)
Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

As x ⇒ ∝, f(x) ⇒ +∝
As x ⇒ -∝, f(x) ⇒ -∝