Answer:
<h2>A. <em><u>2</u></em><em><u>1</u></em><em><u>4</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em></h2>
Step-by-step explanation:
<h3>#CarryOnLearning</h3>

By inspection, it's clear that the sequence must converge to

because

when

is arbitrarily large.
Now, for the limit as

to be equal to

is to say that for any

, there exists some

such that whenever

, it follows that

From this inequality, we get




As we're considering

, we can omit the first inequality.
We can then see that choosing

will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that

.
Answer:
3 more than
Step-by-step explanation:
Hope this correct and Your welcome
So it gives you the diameter but you need the radius of the circle to find the area so to find the radius you just divide the diameter by two. the formula for the area of a circle is A=pi*r^2 so you just multiply 3.14 by 3 squared so you just put it in the calculator as A=3.14*3^2 and you get 28.26 hope this helped
Answer:
cos-1(-4/14)
Step-by-step explanation:
If
4.5=r
3.5=s
2=t
By law of cosines:
