A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH is followed by .
2 answers:
Answer:
<h2>A rotation -90° around point I.</h2><h2>A translation upwards 2 units.</h2><h2>Step-by-step explanation:</h2>The given figures are attached.
We have to find two transformations that help to show that both polygon are congruent.
First transformation would be a rotation -90° around point I.
Second transformation would be a translation upwards 2 units.
Applying these transformation, we would have both polygons at the same position, that will show the congruence between them.
Answer: A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH is a reflection across the x-axis followed by a 90° clockwise rotation about point D
Step-by-step explanation:
If you reflect polygon ABCDE over the x-axis point D will fall over point I from Polygon GFJIH, then by doing a 90° clockwise rotation, the image is congruent, i'll atach an image for you to see the process.
You might be interested in
The fireworks display occur at 550.331 ft
The generic equation for a hyperbola provided by: is the best method for solving the problem in this instance.
-
We presume that the y-axis is where the hyperbola's longer axis lies.
In this instance, the sound traveled a total of 1100 meters, and the value of a can be calculated as follows:
2a = 1100
a = 550ft
Given that the two people are 3 miles apart, we can calculate the value of c in feet as follows:
1 mile = 5280 feet
∴ 3 miles = 15840 ft = c
And this is how we may determine what b is worth:
Our equation is thus given by:
And for this case we want to find the value of x when y = 3ft=15840ft and solving for x we get,
x = 550.331 ft.
The fireworks display occur at 550.331 ft.
Learn more about hyperbola here :
#SPJ1