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sesenic [268]
2 years ago
7

Please help fast need to get this and 6 more done

Mathematics
1 answer:
lara [203]2 years ago
3 0

Answer:

B = 4×4×ㅈ

l = 5 cm

SA= 4×5×ㅈ + 16 ㅈ

SA = 36 ㅈ

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Que How does your tessellation with triangles relate to hexagons and tessellating the plane? Type your response in the space bel
madreJ [45]

For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have

Shape Tessellate?

Octagon No

Hexagon Yes

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5 0
1 year ago
Two adjacent sides of a parallelogram are 6mm and 10mm respectively, and they form an angle measuring 60. Find the area of the p
Snowcat [4.5K]

Answer:

51.96 mm² approximately

Step-by-step explanation:

the first thing you should know is that the area of a rectangle is base*height sin of (

the included angle i.e

Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°

<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>

Aparallelogram= bh sin of sin of the included angle

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately

4 0
2 years ago
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Ainat [17]
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