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gulaghasi [49]
3 years ago
10

Solve for x if 2(5x + 2)^2 = 48

Mathematics
2 answers:
Artyom0805 [142]3 years ago
6 0

Answer:

(c) is the Correct answer of this

Step-by-step explanation:

First divide both sides by 2

then apply (a+b)^2 = a^2+b^2+2ab formula

solve quadratic equation

then apply discriminant formula

Hope you get it dear ☺️

blagie [28]3 years ago
6 0
C is correct I’ve done this one before
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What is x? (7x+1)=(9x-7)
kakasveta [241]

Step-by-step explanation:

Given

7x + 1 = 9x - 7

9x - 7x = 1 + 7

2x = 8

x = 8 / 2

x = 4

Hope it will help :)❤

8 0
2 years ago
an online sporting goods store charges $12 for a pair of athletic socks. shipping is $2 per order. write an expression that hana
djverab [1.8K]
For one pair of socks you pay $12 plus $2 shipping.

Let's use x as the variable for how many pairs of socks someone might buy.

If someone buys 5 pairs of socks, they will pay $62. $12 * 5 + $2

So, we can write the expression as 12x + 2.
6 0
3 years ago
Mathematics question help
Nat2105 [25]

Distance Formula: \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}

Point 1: (9,0)

Point 2: (5,-8)

D = sqrt[ (5 - 9)^2 + (-8 - 0)^2 ]

D = sqrt[ (-4)^2 + (-8)^2 ]

D = sqrt[ 16 + 64]

D = sqrt(80)

Hope this helps!

4 0
2 years ago
Read 2 more answers
What is the perimeter of triangle ABC? 20 units 22 units 24 units 26 units
Alex777 [14]
8[2] + 6[2] = c[2]
64 + 36 = c[2]
100 = c[2]
c = 10

8 + 6 + 10 = 24 units
8 0
2 years ago
Read 2 more answers
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
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