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BlackZzzverrR [31]
3 years ago
10

Uh help ig ? Which product is less than 5/8?

Mathematics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

um 1/2???

Step-by-step explanation:

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7 0
3 years ago
Amelia randomly selects two cards, with replacement, from a normal deck of cards. Calculate the probability that: the first card
Lena [83]

Answer:

1 / 2704

Step-by-step explanation:

Number of cards in a deck = 52

9 of clubs in a deck = 1

10 of clubs in a deck = 1

Probability = required outcome / Total possible outcomes

P(9 of club) = 1 / 52

With replacement ;

Then ;

P(10 of club) = 1 / 52

Hence,

P(9 of club, then 10 of club) = 1/52 * 1/52 = 1 / 2704

3 0
3 years ago
Find the balance of the account using the simple interest formula of I=Prt
prohojiy [21]

Given:

Principal = $1400

Simple rate of interest = 1.25%

Time = 6 month

To find:

The balance of the account after simple interest.

Solution:

The formula for simple interest is

I=\dfrac{P\times r\times t}{100}

Where, P is principal, r is the rate of interest in % and t is time in years.

Time = 6 months

        = \dfrac{6}{12} year

        = 0.5 year

Putting 1400, r=1.25, t=0.5 years.

I=\dfrac{1400\times 1.25\times 0.5}{100}

I=\dfrac{875}{100}

I=8.75

Now, the amount is

A=P+I

A=1400+8.75

A=1408.75

Therefore, the balance of the account after the simple interest is $1408.75.

5 0
3 years ago
Two points are separated on the ground by a distance of 43 km. Can they be placed on a 1 / 25000th map with dimensions 1.32 m on
Wittaler [7]

Answer:

No

Explanation:

The distance between the two points on the ground = 43km

\text{Scale}=\frac{1}{25000}

First, we calculate the distance between the two points in meters.

• 43km = 43,000 m.

Next, determine the distance it will take using the scale.

\begin{gathered} \frac{1}{25000}=\frac{x}{43000} \\ 25000x=43000 \\ x=\frac{43000}{25000} \\ x=1.72m \end{gathered}

The distance between the points using the scale is 1.72m.

Next, we see that the dimensions (1.32 m by 0.85 m) are smaller than the length.

As a final check, calculate the length of the diagonal of the map. The diagonal is usually the longest part.

\text{Diagonal}=\sqrt[]{1.32^2+0.85^2}=1.57m

Since 1.57m is still less than 1.72m, the two points cannot be placed on the map.

7 0
1 year ago
Balancing the equation 121 - X = 49+10+26
Jlenok [28]
121-36=49+10+26.X is eqeal to 36
7 0
4 years ago
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