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user100 [1]
2 years ago
15

Select the three equations that have

Mathematics
2 answers:
MakcuM [25]2 years ago
3 0

Answer:y+2.9=11, 2y+1=17.2, 28.4-y=20.3

Step-by-step explanation:

disa [49]2 years ago
3 0

Answer:

Select all of the equations that have y=8.1 as the solution. Mark all that apply.  

y+2.9=11

12-y=8.1

2y+1=17.2

9+7.2-y=8.2

28.4-y=20.3

Step-by-step explanation:

Select all of the equations that have y=8.1 as the solution. Mark all that apply.  

y+2.9=11

12-y=8.1

2y+1=17.2

9+7.2-y=8.2

28.4-y=20.3

You might be interested in
What is negative 7 minus negative 2
zalisa [80]

Answer:

-5

Step-by-step explanation:

-7 - (-2)

-7 + 2

Example: If you owe someone $7, and you give them $2, how much do you still owe? You are owing him $7 so it's a negative and you give him $2 which is a negative as well since you are giving it to him. So, to answer how much do you still owe, you would add $2  to the $7 you owed, so now, you owe him $5, which is a negative since you OWE him.

Hope this helps:)

3 0
3 years ago
Find cscθ.<br><br>pls answer
ExtremeBDS [4]

Answer:

The answer to your question is csc Ф = \frac{-5}{4}

Step-by-step explanation:

Process

1.- Determine the sign

We must determine csc Ф in the forth quadrangle, here csc is negative.

2.- Determine the hypotenuse

     c² = a² + b²

     c² = 3² + (-4)²

     c² = 9 + 16

     c² = 25

     c = 5

3.- Determine csc Ф

    csc Ф = \frac{hypotenuse}{opposite side}

    csc Ф = \frac{5}{-4}  = \frac{-5}{4}

7 0
2 years ago
Help Please! I will give brainliest!!
seropon [69]
The answer is 32.7 b so the answer is 105 over 10
6 0
2 years ago
Read 2 more answers
Help please!!!!
Sonja [21]

Answer:

you already put this one

6 0
3 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

#SPJ1

7 0
1 year ago
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