Tell me if i did these correctly and i will mark you brainiest

Find the distance between the pair of points. (7, -17) and (-22, 12)

Misha Larkins [42]

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(-22 - 7)^2 + (12 + 17)^2}\\= \sqrt{(-29)^2 + 29^2} = \sqrt{841 + 841} = \sqrt{1682} = 29\sqrt{2}$

7 0

4 years ago

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi

Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$

n days:

This means that $s = \frac{\sigma}{\sqrt{n}}$

Applying the Central Limit Theorem to the z-score formula.

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

5 0

3 years ago

X x is the first five consonants of english alphabet

satela [25.4K]

Consonants are letters that are not vowels a e I o u sometimes y
The first 5 consonants are

a.B.C.D.e.F.G

B
C
D
F and
G

4 0

3 years ago

3/4 cup of flour makes 6 rolls how many cup of flour for 32 rolls

horsena [70]

6 rolls / (3÷4)

Divide 32 rolls by 6 to get the quantity to multiply (3÷4) by.
32 ÷ 6 = 5(1÷3)

5(1÷3) × (3÷4) = 1.25 cups of flour.
Or 1(1÷4) cups

3 0

3 years ago