Answer:
=193.2 cm
Step-by-step explanation:
- Figure out the triangles first
- Area= Base times Height divided by 2
- first figure out one triangle A= (6)(5.2)/2 = 15.6 (brackets means times and the slash means divide
- times it by 2 so you get the area of both triangles (15.6)(2)= 31.2
- Now figure out the rectangles
- Area= Base times Height
- A=(6)(9) = 54
- Then times it by 3 to get the area of all three triangles
- (54)(3)= 162
- Now add 162 and 31.2 and you get 193.2 cm
The given box has the shape of a <u>cuboid</u>, since its <em>height</em> is greater than its <em>width</em>. Thus, the <em>maximum volume</em> for such box is 11200
.
The <u>volume</u> of an object is a measure of it <em>containing</em> capacity. Since the given box has a taller <em>height</em> than its <em>width</em>, then it has the shape of a <em>cuboid</em>. The<u> volume</u> of a cuboid is given as:
volume = length x width x height
= area x height
Given that the <u>sum</u> of the <em>perimeter</em> of its base and its <em>height</em> is not more than 108 inches, we can say; let the sides of the <em>square</em> base be represented by l and its height by h.
Then;
4l + h = 108
Therefore, maximum volume for the box can be attained when l = 20 inches and h = 28 inches.
So that;
4(20) + 28 = 80 + 28
= 108 inches
Thus;
maximum volume = area of the square base x height
= 400 x 28
maximum volume = 11200 
The <u>maximum</u> <u>volume</u> for such a box would be 11200
.
Visit: brainly.com/question/20463446
Answer:
Option B. 36
Step-by-step explanation:
From the figure attached,
ΔLMN ~ ΔPON
Therefore, corresponding sides of these similar triangles will be in the same ratio.



x = 
x = 36
Therefore, measure of side MN = x = 36 units
Option B. will be answer.
Answer:
Segment JK is a chord in circle H
Line LM is a secant to circle H
Step-by-step explanation:
* Lets revise some definition in the circle
- The radius of the circle is a line segment drawn from the center of
the circle to a point on the circumference of the circle
- The chord of a circle is a line segment whose endpoints lie on the
circumference of the circle
- The secant is a line intersect the circle in two points
- The tangent is a line touch or intersect the circle in one point
* Now lets solve the problem
- In circle H
∵ JK is a segment in circle H
∵ Point J lies on the circumference of circle H
∵ Point K lies on the circumference of circle H
∴ Segment JK is a chord in circle H
∵ LM is a line
∵ LM intersect circle H in two points L and M
∴ Line LM is a secant to circle H