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Illusion [34]
3 years ago
6

HELP ME PLS

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

<u>Answer:</u>

Slope = 27/11

AB = 29.15 u

<u>Step-by-step explanation:</u>

<u>Given :- </u>

  • Two points are given to us .
  • The points are A(7,15) and B(18,42)

<u>To Find :- </u>

  • The slope of the line .
  • The length of line AB .

We can find the slope of the line passing through the points ( x_1,y_1) and ( x_2,y_2)as ,

\implies m = \dfrac{ y_2-y_1}{x_2-x_{1}}

  • Plug in the respective values ,

\implies m = \dfrac{ 42-15}{18-7} \\\\\implies \boxed{ m = \dfrac{ 27}{11 }}

<u>Hence the slope of the line is 27/11 .</u>

\rule{200}2

<u>Finding the length of AB :-</u>

  • We can find the distance between them by using the Distance Formula .

\implies Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2} \\\\\implies Distance =\sqrt{ (18-7)^2+(42-15)^2 }  \\\\\implies Distance =\sqrt{ 11^2 + 27^2 } \\\\\implies Distance =\sqrt{ 121 + 729 } \\\\\implies Distance = \sqrt{ 850} \\\\\implies \boxed{ Distance = 29.15 \ units }

<u>Hence the length of AB is 29.15 units </u>.

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Step-by-step explanation:

The triangle is right angled , so :

tan S = UT/ST

tan S = 2/1

tan S = 2

S = tan^{-1}2

S = 63.4

5 0
3 years ago
1. Saiz buys a Playstation 5 for $500 with a credit card carrying a 21% Annual Percentage Rate (APR) and each month she will pay
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3 years ago
Which of the following is a like radical to RootIndex 3 StartRoot 7x EndRoot?
lana [24]

Answer:

A. 4 (RootIndex 3 StartRoot 7 x EndRoot)  or 4(\sqrt[3]{7x})

Step-by-step explanation:

Given:

A radical whose value is, r_1=\sqrt[3]{7x}

Now, we need to find the like radical for r_1.

Let the like radical be r_2.

As per the definition of like radicals, like radicals are those that can be expressed as multiples of each other.

So, if two radicals r_1\ and\ r_2 are like radicals, then

r_1 = n \times r_2&#10;

Where, 'n' is a real number.

Here, r_1=\sqrt[3]{7x}

Now, let us check all the options .

Option A:

4 (RootIndex 3 StartRoot 7 x EndRoot) or r_2=4\sqrt[3]{7x}

Now, we observe that r_2 is a multiple of r_1 because

r_2=4\times \sqrt[3]{7x}\\\\ r_2=4\times r_1..............(r_1=\sqrt[3]{7x})

Therefore, option A is correct.

Option B:

StartRoot 7 x EndRoot or r_2=\sqrt{7x}

As the above radical is square root and not a cubic root, this option is incorrect.

Option C:

x (RootIndex 3 StartRoot 7 EndRoot) or r_2=x\sqrt[3]{7}

As the term inside the cubic root is not same as that of r_1, this option is also incorrect.

Option D:

7 StartRoot x EndRoot or r_2=7\sqrt{x}

As the above radical is square root and not a cubic root, this option is incorrect.

Therefore, the like radical is option (A) only.

4 0
3 years ago
Read 2 more answers
Please solve quickly ​
Crazy boy [7]

Answer:

75.36

hope this helps :)

5 0
2 years ago
Which two days had a ratio of 2:5 computers sold?
Nana76 [90]

Answer:

A. Wednesday to Friday

Step-by-step explanation:

Wednesday/Friday=6/15=2/5

2/5=2:5

7 0
3 years ago
Read 2 more answers
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