How do i do this problem?
1 answer:
You might be interested in
A boy stands 1 meter away from a lamppost. He is 1.8 meters tall and casts a shadow 2 meters long in the light from the lamp
The diagram is attached below using the given information
We have two similar triangle
Triangle ACD is similar to triangle ABE. So the sides are in proportional
AC = AB + BC = 3m
2x = 1.8 * 3 (cross multiply)
2x = 5.4
Divide by 2 on both sides
x = 2.7
Height of Lamppost is 2.7 meter
A line parallel to the given one will have the same slope, 0.5. For the purpose here, it is convenient to start with a point-slope form of the equation, then simplify. For slope m and point (h, k), the equation of the line can be written as
... y = m(x -h) +k
We have m=0.5, (h, k) = (-9, 12), so the equation is ...
... y = 0.5(x +9) +12
... y = 0.5x +16.5
