Answer:
It isn't much help, but the answer is NOT C. 6
I just took the test and C was not the answer !! I will update this if I figure out what it was.
The expressions that represent number of tiles that Devon used on her mosaic:
A. 20 + 2t + 2c
D. 20 + t + t + c + c
<h3>What is an expression?</h3>
An expression refers to a mathematical equation which shows the relationship between two or more numerical quantities or variables.
For the expressions that represent number of tiles that Devon used on her mosaic:
- Let the triangle tiles be t.
- Let the circle tiles be c.
- Two rows of t triangle tiles = t + t = 2t.
- Two rows of c circle tiles = c + c = 2t.
Mathematically, the expression is given by:
Total tiles = 20 + t + t + c + c
Total tiles = 20 + 2t + 2c.
Read more on expressions here: brainly.com/question/12189823
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Complete Question:
Devon made a mosaic in art class with different-shaped tiles. She started by putting 2 rows of t triangle tiles at the top of the mosaic and 2 rows of c circle tiles at the bottom. She finished by putting 20 square tiles in between the triangle and circle tiles.
Pick all the expressions that represent how many tiles Devon used on her mosaic.
A. 20 + 2t + 2c
B. 20 + 4 ( t + c )
C. 2 ( 20 + t + c )
D. 20 + t + t + c + c
Answer:
Answer: g(x)=. Step-by-step explanation: We are given that: f(x)=x². We have to find g(x). Since, we are given that g(3)=1. Hence, we will ... · g of x would equal (1/3x)^2 because if x was 6 y, g(x), would be 4
Step-by-step explanation:
Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
