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Drupady [299]
3 years ago
7

You start driving east for 14 miles, turn left, and drive north for another 6 miles. At the end of driving, what is your straigh

t line distance from your starting point? Round to the nearest tenth of a mile.
Mathematics
1 answer:
denpristay [2]3 years ago
5 0

Answer: 15.2

Step-by-step explanation:

(14)^2 + (6)^2 = c^2

196 + 36 = c^2

232 = c^2

Square root both sides

15.231546 = c

15.2 ≈ c

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Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books
AlladinOne [14]

<u>Answers</u>

19 fiction books

7 nonfiction books


<u>Explanation</u>

x + y = 26  ............................................. (i)

x – y = 12  ............................................ (ii)

Elliot added the two equations and the result was

2x = 38.

Dividing both sides by 2;

x = 19

There are 19 fiction books.

Substituting x in equation (i),

x + y = 26             when x = 19

19 + y = 26

y = 26 - 19

   = 7

There are 7 nonfiction books

4 0
3 years ago
Read 2 more answers
Laticia randomly selected 25% of the seventh-grade students in her school an asked them their favorite season.Of the students su
Afina-wow [57]
About 204 students would choose summer , I found this because 25% is one quarter of a whole and to get the whole you multiply by four so take 51 and multiply by four to get 204
3 0
3 years ago
Someone help please.
malfutka [58]

Answer:

$27

Step-by-step explanation:

If the table was marked up 125%, you can find the retail price of it this way:

20 + 1.25(20) = retail price

$45 = retail price.

To find 40% off of that, use

$45 - .4($45) = sale price

$27 = sale price (aka discount price)

5 0
3 years ago
Given △QRS ~ △XYZ, what is the value of tan(Q)?
VladimirAG [237]
Since the triangles are similar the ratios of the lengths of corresponding sides are equal.

tan Q = opp/adj = RS/QS = YZ/XZ = 9/12 = 3/4
8 0
3 years ago
Read 2 more answers
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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