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leonid [27]
3 years ago
14

Parallel Lines PLEASE HELP I NEED ASAP!

Mathematics
2 answers:
Musya8 [376]3 years ago
8 0

Answer: Choice B

Yes. Right triangles formed on parallel lines have proportional side lengths and congruent angles.

====================================================

Explanation:

Parallel lines always have equal slopes, but different y intercepts.

Recall that slope = rise/run.

The "rise" is the vertical portion of the triangle, while the "run" is the horizontal portion.

So let's say we had a slope of rise/run = 2/3. This means rise = 2 and run = 3.

If we had something like rise/run = 4/6, then that reduces to 2/3, showing that 4/6 = 2/3. They are the same slope.

We can use the SAS similarity theorem to prove the triangles formed in the diagram are congruent based on what is discussed above.

Because the triangles are similar, this means the corresponding angles are congruent. One such pair is the pair of right angles shown.

Karolina [17]3 years ago
3 0

Answer:

B

Step-by-step explanation:

The triangles do have equal angles and proportional sides, because they are bot right triangles formed on parallel lines.

:)ur welcome

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goldfiish [28.3K]

Answer:

f(-7)=0.

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f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

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\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

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Answer:

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Step-by-step explanation:

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Answer:

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The general formula for the nth term of a geometric sequence i

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