Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5
Step-by-step explanation:
The answer is D. The ones on the left are the domain. The ones on the right which the arrows point to are the range
Answer:
C
Step-by-step explanation:
Okay! Time to use the Pythagoras theorem.
a^2 + b^2 = c^2
4^2 + 7^2 = x^2
16 + 49 = c^2
65 = c^2
Let's take the square root of both sides to get
c ~ 8.06
C
:)
0.8 is greater than 0.08, the reason for that is that 0.8 is equal to 8/10=80/100 and 0.08 is equal to 8/100. As a percentage, 0.8 would be 80% and 0.08 would be equal to 8%.
Step-by-step explanation:
<u>Using Pythagorus theorem</u> :
(A)
(B)
