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ollegr [7]
3 years ago
12

In investing $6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple inter

est. The rest was invested in a riskier mini-mall development plan paying 9% annual simple interest. The combined interest earned for the first year was $428. How much money was invested at each rate?
Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

$ 2,600 was invested at 4% and $ 3,600 was invested at 9%.

Step-by-step explanation:

Given that in investing $ 6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest, and the rest was invested in a riskier mini-mall development plan paying 9% annual simple interest, and the combined interest earned for the first year was $ 428, to determine how much money was invested at each rate, the following calculation must be performed:

3000 x 0.04 + 3200 x 0.09 = 408

2500 x 0.04 + 3700 x 0.09 = 433

2600 x 0.04 + 3600 x 0.09 = 428

Therefore, $ 2,600 was invested at 4% and $ 3,600 was invested at 9%.

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Answer:

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Step-by-step explanation:

In f(x)=a\cos(b(x-c))+d, b represents a constant related to the period of the function. Here's how it's related:

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We're given T=12\pi, so solving for b:

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3 years ago
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Answer:

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Step-by-step explanation:

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<h3>What is the smallest possible value of m?</h3>

Since it follows from the task content that the product of 1540 and m is a square number and the smallest possible small number is; 1.

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