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dalvyx [7]
2 years ago
15

The value of d is an integer such that 0.8

Mathematics
1 answer:
jenyasd209 [6]2 years ago
4 0

Answer:

ok then go find sth to do with uh life

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Bas_tet [7]

Answer:

2)

Step-by-step explanation:

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2 years ago
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Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x.<br><br> show your work
aliya0001 [1]

Answer:

x=14

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

so

corresponding sides

MO≅PQ

MN≅PR

ON≅QR

corresponding angles

∠M≅∠P

∠O≅∠Q

∠N≅∠R

therefore

MN=PR

substitute the given values

32=3x-10

solve for x

3x=32+10

3x=42

x=14

3 0
3 years ago
Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing,
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A.  When f(x) becomes g(x) = f(x) + 2, the graph of f(x) is shifted upward 2 units.

B  The graph of f(x) is reflected in the x-axis and then vertically compressed by a factor of 1/2.
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6 0
3 years ago
The cosine of 23° is equivalent to the sine of what angle
Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

\cos(90^\circ-x)=\sin(x)

or

\sin(90^\circ-x)=\cos(x)

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0
3 years ago
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