It looks like you want to compute the double integral

over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.
Convert to polar coordinates, in which <em>D</em> is given by the set
<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}
and
<em>x</em> = <em>r</em> cos(<em>θ</em>)
<em>y</em> = <em>r</em> sin(<em>θ</em>)
d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>
Then the integral is

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Answer:
Option D. 8 units
Step-by-step explanation:
step 1
Find the area of rectangle
The area of rectangle is

step 2
Find the length side of the square with the same area of rectangle
The area of a square is

where
b is the length side of the square
we have

substitute

take the square root both sides

therefore
The length side of the square is 8 units
Answer:
if its a 90 degree angle u will say 90 -46 to get m<2
if is a 180 degree angle u will say 180-46 to get m<2
hope this helped :) brainliestn pls