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Aleonysh [2.5K]

3 years ago

5

✓ = 2x²-4 Is it linear or nonlinear

1 answer:

kykrilka [37]3 years ago

4 0

Nonlinear because it is squared it is a quadratic

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Whats 1x to the 3rd power and y to the third power divided by 3x squared and y to the 4th power

Alex787 [66]

The answer would be 1 by 3 y to the first power

6 0

3 years ago

What is the distance between -4 and -1 on a number line

icang [17]

Answer: The distance is 3.

Step-by-step explanation: Start on a number line from 0. Go back 4 and mark it at -4. Then go back to 0 and go back 1 and mark it at -1. If you count the space between -4 and -1 you will get 3 spaces.

6 0

4 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

Read more at:

brainly.com/question/14320476

7 0

3 years ago

The vertices of triangle PQR are given in the standard (x,y) coordinate plane below. What is the area, in the square coordinate

alekssr [168]

Answer:

Area = 12

Step-by-step explanation:

Given

See attachment

Required

Area of $\triangle PQR$

From the attached image, we have:

$P = (6,10)$

$Q = (10,8)$

$R = (6,4)$

The area is then calculated as:

$A = \frac{1}{2}|(x1y2 - x2y1) + (x2y3 - x3y2) + (x3y1 - x1y3)|$

So, we have:

$A = \frac{1}{2}|(6*8 - 10*10) + (10*4 - 6*8) + (6*10 - 6*4)|$

Using a calculator:

$A = \frac{1}{2}|-24|$

Remove absolute bracket

$A = \frac{1}{2} * 24$

$A = 12$

8 0

3 years ago

Please helppppppppppppp

Lilit [14]

Answer:

y = - x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 1 and c = 2 , then

y = - x + 2 ← equation of line

3 0

3 years ago