What is the value of h(–2) when h(x) = 3x + 1? h(

What is the value of x? 6+8x2=5x

Gala2k [10]

Answer:

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floor gang oug

3 0

2 years ago

Read 2 more answers

In drawing a histogram, which of the following suggestions should be followed?

ELEN [110]

Answer:

B) The heights of the bear should equal the class frequency.

Step-by-step explanation:

In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.

8 0

2 years ago

HELP!!! URGENT!!! I WILL GIVE BRAINLEIST THING

lisov135 [29]

Answer:

Horizontal distance = 0 m and 6 m

Step-by-step explanation:

Height of a rider in a roller coaster has been defined by the equation,

y = $\frac{1}{3}x^{2}-2x+8$

Here x = rider's horizontal distance from the start of the ride

i). $y=\frac{1}{3}x^{2}-2x+8$

$=\frac{1}{3}(x^{2}-6x+24)$

$=\frac{1}{3}[x^{2}-2(3x)+9-9+24]$

$=\frac{1}{3}[(x^{2}-2(3x)+9)+15]$

$=\frac{1}{3}[(x-3)^2+15]$

$=\frac{1}{3}(x-3)^2+5$

ii). Since, the parabolic graph for the given equation opens upwards,

Vertex of the parabola will be the lowest point of the rider on the roller coaster.

From the equation,

Vertex → (3, 5)

Therefore, minimum height of the rider will be the y-coordinate of the vertex.

Minimum height of the rider = 5 m

iii). If h = 8 m,

$8=\frac{1}{3}(x-3)^2+5$

$3=\frac{1}{3}(x-3)^2$

(x - 3)² = 9

x = 3 ± 3

x = 0, 6 m

Therefore, at 8 m height of the roller coaster, horizontal distance of the rider will be x = 0 and 6 m

6 0

2 years ago

Point R is located at (1, 2) on a coordinate grid. Point S is located at (4, 5) on the same

Aleksandr-060686 [28]

Answer:

4.2 units

most likely answer choice B

Step-by-step explanation:

(1, 2) and (4, 5)

To find the distance between two points, we use the distance formula:

$d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }$

Let's plug in what we know.

$d = \sqrt{(4 - 1)^2 + (5 - 2)^2 }$

Evaluate the parentheses.

$d = \sqrt{(3)^2 + (3)^2 }$

Evaluate the exponents.

$d = \sqrt{(9) + (9) }$

Add.

$d=\sqrt{18}$

Evaluate the radical.

d = 4.24

Round to the nearest tenth.

d = 4.2 units

*note: The answer choice is 4.6. I'm not sure if that is a typo on someone's end, but the distance between these two points is exactly 4.24264068712 units.

Hope this helps!

6 0

2 years ago

in the year 2010, the luxury bike industry had two bike manufactures splendor and passion with the market shares of 30% and 70%,

kari74 [83]

Answer: 50%

Step-by-step explanation:

In 2010, there were only 2 bike manufacturers and they had market shares of 30% and 70%.

A new manufacturer joins the market and captures 10% of the market share and Splendor increases to 40% of market share.

Market shares:

Yamaha = 10%

Splendor = 40%

Passion = 100% - 10% - 40%

= 50%

8 0

2 years ago

What is the value of h(–2) when h(x) = 3x + 1? h(–2) =