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Alina [70]
4 years ago
9

What is the value of h(–2) when h(x) = 3x + 1? h(–2) =

Mathematics
1 answer:
olganol [36]4 years ago
7 0

Answer:

3x+1

Step-by-step explanation:

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Which symbol completes the statement 2/3 ___ 5/8
kondaur [170]
It goes 2/3  1/2 and 5/8 


so the answer is 1/2 or the way I originally got it 3/6

HOPE THIS HELPS!!!!
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3 years ago
Create the equation of the line that passes through the point (1, -10) and is perpendicular to y=-1/3x+5
Ber [7]

Answer:

y = 3x - 13

Step-by-step explanation:

y = -1/3x + 5

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of perpendicular line is 3

y = mx + b

y = 3x + b

Using (1,-10)

-10 = 3(1) + b

-10 = 3 + b

b = -13

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4 0
2 years ago
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AlekseyPX
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6 0
3 years ago
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Bumek [7]

Answer:

Hope that answers your question

4 0
3 years ago
compare the right-hand and left-hand derivatives to show that the function is not differentiable at the point P. find all points
Softa [21]
f(x)=  \left \{ {{ \sqrt{x} } \atop {2x-1}} \right. &#10;\\&#10;\\ f'(x)=  \left \{ {{  \frac{1}{2\sqrt{x}} } \atop {2}} \right. &#10;\\&#10;\\  f'(1)=  \left \{ {{  \frac{1}{2}} \atop {2}} \right. &#10;\\&#10;\\ f'(1^-) \neq f'(1^+)

Therefore, the function is not differentiable at x = 1.

f(x)= \sqrt{x} &#10;\\&#10;\\f'(x)= \frac{1}{2 \sqrt{x} } &#10;\\&#10;\\f'(0)=\frac{1}{2 \sqrt{0} } = \infty

Therefore, the function is not differentiable at x = 0.
3 0
3 years ago
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