Todd Wallace works as the chief knowledge officer for Pennsylvania Lumber Company. He has been given the responsibility to creat
1 answer:
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Answer:
public static int powOfTwo(int input) {
return input*input;
}
You will have to call this method in main
for printing it, write
System.out.println(powOfTwo(your number));
in public static void main(str[]args) {
}
Explanation:
Let, DG is the datagram so, DG= 2400.
Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.
Let, M is the MTU so, M=700.
Let, IP is the IP header so, IP= 20.
Let, id is the identification number so, id=422
Required numbers of the fragment =
Insert values in the formula =
Then, = =
The generated numbers of the fragment is 4
- If FV = 1 then, bytes in data field of DG=
and id=422 and FO=0 and F=1.
- If FV = 2 then, bytes in data field of DG=
and F=1.
- If FV = 3 then, bytes in data field of DG=
and F=1.
- If FV = 4 then, bytes in data field of DG=
and id=422 and FO=255
and F=0.