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3 years ago

9

Hey what's

\sqrt[5]{1024} " align="absmiddle" class="latex-formula">

2 answers:

Serggg [28]3 years ago

7 0

Hello the answer is:

4

Tomtit [17]3 years ago

4 0

Answer:

$4 \\ \: is \: your \: answer \: mate$

<h2>I <em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em></h2>

<em><u>enjoy</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>day</u></em>

<em><u>#Captainpower</u></em><em><u>|</u></em><em><u>~</u></em>

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Need help solving please.

3241004551 [841]

Answer:

25/36

Step-by-step explanation:

<u>Solved in steps:</u>

- 2/9 - ( -11/12) =
- 2/9 + 11/12 =
- 2*4/9*4 + 11*3/12*3 =
-8/36 + 33/36 =
25/36

Simplest fraction is 25/36

3 0

3 years ago

Pachacha [2.7K]

Answer:

this is too old

Step-by-step explanation:

7 0

3 years ago

Rename numbers 50 ten thousands

N76 [4]

50,000 would be 50 ten thousands

5 0

3 years ago

The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F

OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

$\frac{(1 -0.99)}{2}=0.005$

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

$n=\frac{z^2pq}{e^2}$

Where, e is the margin of error,

Substitute the respective values.

$n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89$

Hence, the Sample size is 1918.89035

4 0

3 years ago

What is the value of c?<br> 13c − 22 = −17c + 14

sveta [45]

13c - 22 = -17c + 14
13c + 17c = 14 + 22
30c = 36
c = 36/30
c = 6/5

4 0

3 years ago