The correct answer is:
(x,y) = (6,2)
Option A would be the correct one.
Answer:
10 days
Step-by-step explanation:
Mogaka and Ondiso working together can do a piece of job in 6 days. Mogaka working alone takes 5 days longer than Ondiso. How many days does it take Ondiso to do the work alone?
Let us represent :
The number of days
Mogaka worked alone = x
Ondiso worked alone = y
Total days worked together = T
Mogaka and Ondiso working together can do a piece of job in 6 days.
Hence,
1/x + 1/y = 1/T
Mogaka working alone takes 5 days longer than Ondiso.
x = y + 5
Therefore:
1/y + 5 + 1/y = 1/6
Multiply all through by (y+5)(y)
= y + y + 5 = (y+5)(y)/6
= 2y + 5/1 = (y+5)(y)/6
Cross Multiply
6( 2y + 5) = (y+5)(y)
12y + 30 = y² + 5y
= y² + 5y - 12y - 30 = 0
= y² - 7y - 30 = 0
Factorise
= y² +3y - 10y - 30 = 0
y(y + 3) - 10(y + 3) = 0
(y + 3)(y -10)= 0
y + 3 = 0, y = -3
y - 10 = 0
y = 10 days
Note that
The number of days Ondiso worked alone = y
Hence, it takes 10 days for Ondiso to work alone
Marked down means discount....$24000 is the cost price and 20%is the discount....
$24000 equal 100% because it is the original cost
?????? equal 20%.now we want to find out how much is 20% of 24000
$24000×20÷100......you then get $4800.
then $24000-$4800 which will be $19200
82
Atruck 120+.60
Btruck 60+.90
A.120.6║ B. 60.9 ║1
A.121.2║ B.61.8 ║2
A.121.8║ B.62.7 ║3
A.122.4║ B.63.6 ║4
A.123.0║ B.64.5 ║5
A.123.6║ B.65.4 ║6
A.124.2║ B.66.3 ║7
A.124.8║ B.67.2 ║8
A.125.4║ B.68.1 ║9
A.126.0║ B.69.0 ║10
A.126.6║ B.69.9 ║11
A.127.2║ B.70.8 ║12
A.127.8║ B.71.7 ║13
A.128.4║ B.72.6 ║14
I THINK YOU GET IT