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yanalaym [24]
3 years ago
7

Question and possible answers in picture.

Mathematics
2 answers:
attashe74 [19]3 years ago
7 0

Answer:

975 feet

Step-by-step explanation:

1 inch = 150 feet

6.5 inches = 10 x 6.5 = 975 feet

Hope this helps!

                 

natka813 [3]3 years ago
4 0
Well first off you would have to multiply the 6.5 by then 150 to get your answer and it is 975 so yes that is the right answer
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insens350 [35]
Yes you did those two correctly

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As a nurse, part of your daily duties is to mix medications in the proper proportions for your patients. For one of your regular
spayn [35]

Answer:

10 milligrams of Medication A

Step-by-step explanation:

We'll write proportions/ratios for this:

20:16 is the usual proportion, and x:8 is this week's dose. The ratio from A to B has to be equal, so

20/16 = x/8

Cross-multiply:

(20)(8) = (16)(x)

160 = 16x

divide both sides by 16

x = 10

Please let me know if you have questions about this answer.

5 0
3 years ago
The vertices of a hyperbola are located at (−4, 1) and (4, 1). The foci of the same hyperbola are located at (−5, 1) and (5, 1).
topjm [15]

Answer:

x^2\ 16 - y^2/9 = 1

step-by-step explanation:

soooo the equation for a hyperbola that is horizontal is x^2/a^2 - y^2/b^2 = 1

a hyperbola should always equal one so dont forget that when writing your equation becuase it is easy to forget.

it helps to graph this so you can see it better

to find a it is the distance from the center to the vertices which is 4 so in the equation you will write 16 becuase it is a^2

then you need to find b. to get b you have to figure out that c is the distance from the center to the foci which is 5 and it is all related to the plythagorm theorum becuase it forms a right triangle. so you do c^2 - a^2 = b^2

you get 9 for b^2 because 25-16=9 and so you put that in the equation

3 0
3 years ago
Read 2 more answers
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
Law of Cosine/Sine problem.
storchak [24]
Either or can be used with any triangle...I personally find the law of sines is often more compact as in this case we can just say;

(sin115)/18=(sin40)/c  (with no need for b or B as would be needed with the law of cosines...)

c=18(sin40)/(sin115)

c≈12.77


4 0
3 years ago
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