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2 years ago

13

In Buffalo, New York, the temperature was "14 °F in the morning. If the temperature drops 7°F, and then rose 9°F, what is the te

mperature now?

1 answer:

elena55 [62]2 years ago

7 0

Answer:

16 Degrees

Step-by-step explanation:

14-7=7 7+9=16

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Write an algebraic expression that represents each purchase.

Svetradugi [14.3K]

Answer: Both answers will be

$15x+18$

Step-by-step explanation:

Since we have given that

Cost of soccer balls = $15

Cost of baseball = $6

Cost of sweat socks = $5

a) Mr. Tonkery bought x number of soccer balls and 3 base balls .

So, our algebraic expression will be

$15x+3\times 6\\\\=15x+18$

b) Dennis, Eddie and Felix are on a base ball team. They each bought a baseball and x pair of sweat socks .

Since there are 3 members in a base ball team ,

Number of base ball they will purchase is given by

$3\times 6=18$

Number of sweat socks they will bought is given by

$5\times x\times 3=15x$

Total number they will purchase is given by

$15x+18$

Hence, both answers will be

$15x+18$

6 0

2 years ago

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$

Another identity:

$\displaystyle \large{\sin^2x+\cos^2x=1}$

Therefore:

$\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}$

Hence proved, this is proof by using identity helping to find the specific identity.

6 0

2 years ago

amy buys 50 computers. she pays £160 for each computer. amy is going to sell some of the computers. she wants to get at least 35

Dmitry [639]

She need to sell 7 computers

3 0

3 years ago

On a blueprint with a scale of 1 cm = 4 ft, the length of the wall is 9 cm. If the scale of the blueprint were 1 cm = 3 ft, what

r-ruslan [8.4K]

Answer:

The length of the wall would be 12 cm

Step-by-step explanation:

step 1

we know that

On a blueprint with a scale of 1 cm = 4 ft, the length of the wall is 9 cm

so

The actual length of the wall is equal to ------> 9*4=36 ft

step 2

If the scale of the blueprint were 1 cm = 3 ft

then

The length of the wall in the new blueprint would be ----> 36/3=12 cm

3 0

3 years ago

Determine the length of side c in each of the the triangles below?

Kipish [7]

There are no triangles

5 0

3 years ago