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LenKa [72]
3 years ago
9

What is 15/22 as a repeating decimal?

Mathematics
2 answers:
Bingel [31]3 years ago
8 0
0.6818 is the correct answer
andrew11 [14]3 years ago
6 0

Answer:

0.6818

Step-by-step explanation:

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What is x for the the problem y=6x + 8
Misha Larkins [42]
If Y is 8, we solve by subtracting 8 on both sides,

0 = 6x

Divide by 6,

0 = x

x is equal to 0
5 0
3 years ago
To simplify5(2x-7) use distributive property
sveta [45]

Answer:

10×-35

Step-by-step explanation:

5×2=10

5×7=35

So the answer is 10x-35

8 0
3 years ago
The altitude of mt. makalu is 8485meters,find its heights in centimeter​
ad-work [718]

Answer:

the answer is 848500 centimetres

Step-by-step explanation:

we have to multiply the value by 100.

hope it helps.

5 0
3 years ago
Read 2 more answers
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
Find a vector 3 units long in the opposite direction from v = 〈3, 1,-4).
lutik1710 [3]

Unit vector along the direction v = <3,1,-4> is :

\hat{v} = \dfrac{3i + j  -4k}{\sqrt{3^2 + 1^2 + 4^2}}\\\\\hat{v} = \dfrac{3i + j -4k}{5.1}

So, unit vector opposing the \hat{v} is :

\hat{v'} = -\hat{v}\\\\\hat{v'} = -( \dfrac{3i + j -4k}{5.1})\\\\\hat{v'} = \dfrac{-3i - j +4k}{5.1}

so, vector of magnitude 3 units in opposite direction from v is :

\vec{V} = 3\hat{v'}\\\\\vec{V} = \dfrac{3}{5.1}( -3i -j+4k)

Hence, this is the required solution.

5 0
3 years ago
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