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3 years ago

Find Measures in Intersecting Circles

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

A bybybybybybynybybybybyvtvtvttvtvvtvttvtvtvvtvt

Rufina [12.5K]3 years ago

5 0

7 in. Because if the diameter of D is 4 then the radius is of circle D is 2 then at then you subtract that from the 9 inches (from line A to D) and you get 7 inches (from A to C)

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10000x30 1000x30 100x30 10x 30

maksim [4K]

Answer:

300000

30000

3000

300

Step-by-step explanation:

Use the zero's trick for 10's.

4 0

2 years ago

Factorise 10x squared +19x+6

melomori [17]

Answer:

The answer is (2x+3)(5x+2)

6 0

3 years ago

Read 2 more answers

A habitat of prairie dogs can support mmm dogs at most.

Sloan [31]

Answer:

The correct answer is p = K × x × (m - p) , where K is the constant of proportionality and x is the current population of the habitat.

Step-by-step explanation:

A habitat of prairie dogs can support m dogs at most.

Let us consider the current population of the habitat be x.

Given the condition that the habitat's population, p, grows proportionally to the product of the current population (x) and the difference between m and p.

Thus the proportional equation would look like:

p ∝ x × (m - p)

⇒ p = K × x × (m - p) , where K is the constant of proportionality.

Thus the equation describing the above mentioned relationship is given by the above equation.

3 0

3 years ago

The leopard population in an African wildlife area is currently 17. Due to a new conservation effort, conservationists hope the

kykrilka [37]

Answer:

$a{_n} = 17 + (n - 1)4$ for n = 1, 2, . . . , 20.

Step-by-step explanation:

This is an arithmetic sequence, because the population is said to increase by 4 animals yearly. The formula for the nth term in an arithmetic sequence is given by:

$a{_n} = a{_1} + (n - 1)d$ where $a_n$ is the nth term, [/tex]a_1[/tex] is the first term, n = 1, 2, . . . and d is the common difference.

Since they are currently 17, this implies that the first number in the population sequence will be 17. In order words, the first term is 17.

Since they increase by 4 yearly, then the common difference is 4.

Since it's for 20years, the n = 1, 2, . . ., 20. The explicit formula is therefore:

$a{_n} = 17 + (n - 1)4$ for n = 1, 2, . . . , 20.

8 0

3 years ago

What equation best models this data?(use y to represent the population of rabbits and t to represent the year, assuming that 201

liraira [26]

If we see the data closely, a pattern emerges. The pattern is that the ratio of the population of every consecutive year to the present year is 1.6

Let us check it using a couple of examples.

The rabbit population in the year 2010 is 50. The population increases to 80 the next year (2011). Now, $\frac{80}{50}=1.6$

Likewise, the rabbit population in the year 2011 is 80. The population increases to 128 the next year (2012). Again, $\frac{128}{80}$ $=1.6$

We can verify the same ratio with all the data provided.

Thus, we know that the population in any given year is 1.6 times the population of the previous year. This is a classic case of a compounding problem. We know that the formula for compounding is as:

$F=P\times r^n$

Where $F$ is the future value of the rabbit population in any given year

$P$ is the rabbit population in the year "0" (that is the starting year 2010) and that is 50 in this question. (please note that there is just one starting year).

$r$ is the ratio multiple with which the rabbit population increases each consecutive year.

$n$ is the nth year from the start.

Let us take an example for the better understanding of the working of this formula.

Let us take the year 2014. This is the 4th year

So, the rabbit population in 2014 should be:

$F_{2014} =50\times(1.6)^4\approx328$

This is exactly what we get from the table too.

Thus, $F=P\times r^n$ aptly represents the formula that dictates the rabbit population in the present question.

4 0

3 years ago