Answer:
2x^2 + x - 1
If I did anything you didn't understand let me know so I can explain.
Step-by-step explanation:
All of them are quadratics so let's use that.
The first one is 2x^2 + x - 1. To find the axis of symmetry the strategy is usually to find the two zeroes of a quadratic and pick the number between them. Something to notice though is that 2x^2 + x - 1 is just 2x^2 + x sshifted down 1, so they both have the same axis of symmetry. So I am going to ignore the constant, because then finding the zeroes is much much simpler. I am going to do this with all opions.
So 2x^2 + x - 1 I am just going to use 2x^2 + x. If you factor out an x you get x(2x + 1) So now we have it in factored form and we know the zeroes are 0 and -1/2. The number directly in between these is -1/4, so the axis of symmetry is x = -1/4. I don't know if there is only one with that axis of symmetry so i am going to check the rest.
2x^2 - x + 1 means we are only going to look at 2x^2 - x. factoring we get x(2x - 1) so the zeroes are 0 and 1/2, so the axis of symmetry is at 1/4.
x^2 + 2x - 1 we only use x^2 + 2x. Factored form is x(x+2) so zeroes are 0 and -2 whichh means axis of symmetry is -1
x^2 - 2x + 1 has the same axis of symmetry as x^2 - 2x, which has zeros at 0 and 2 so the axis of symmetry is at 1.
So yep, it was just the first one.
The answer is a. mean. This is the same as the average. (The median is different. It is the number in the middle of all the numbers when they are arranged from smallest to largest. There is no summation or division required in order to determine it.)
Answer:
y=2/3
Step-by-step explanation:
Answer:
The length of a side of the square is 6.3 units.
Step-by-step explanation:
When given vertices for a given shape, the length of the side is calculated using the formula:
√(x2 - x1)² + (y2 - y1)²
When given vertices (x1 , y1) and (x2 , y2)
Square ABCD has vertices A(-2,-3), B(4, -1), C(2,5), and D(-4,3). Find the length of a side
Side AB : A(-2,-3), B(4, -1)
√(x2 - x1)² + (y2 - y1)²
= √(4 -(-2))² + (-1 -(-3))²
= √ 6² + 2²
= √36 + 4
= √40
= 6.3245553203
≈ 6.3 units
B(4, -1), C(2,5),
√(x2 - x1)² + (y2 - y1)²
= √ (2- 4)² + (5- (-1))²
= √-2² + 6²
= √4 + 36
= √40
= 6.3245553203
≈ 6.3 units
C(2,5), D(-4,3).
√(x2 - x1)² + (y2 - y1)²
= √(-4 - 2)² + (3 - 5)²
= √-6² + -2²
= √36 + 4
= √40
= 6.3245553203
≈ 6.3 units
A(-2,-3), D(-4,3).
√(x2 - x1)² + (y2 - y1)²
= √(-4 -(-2))² + (3 - (-3))²
= √-2² + 6²
= √4 + 36
= √40
= 6.3245553203
≈ 6.3 units
