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3 years ago

PLS HELP WILL GIVE BRAINIEST!!!

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

5 0

Answer:

We would have to know the y value associated with each x value to know which one(s) best approximated the root(s

Step-by-step explanation:

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A lawyer commutes daily from his suburban home to his midtown office. The average time for a one-way trip is 24 minutes, with a

gogolik [260]

Answer:

Step-by-step explanation:

a) Probability-Above 30 min = 5.72% = .0572

b) Probability-Above 15 min = 99.11% = .9911

c) *Probability-Between 1 - 59.49% = .4051

d) 19.136 minutes z = -1.28

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3 years ago

The velocity function, in feet per second, is given for a particle moving along a straight line. Find (a) the displacement and (

AveGali [126]

Answer:

(a) 2 feet.

(b) 2 feet.

Step-by-step explanation:

We have been given that the velocity function $v(t)=\frac{1}{\sqrt{t}}$ in feet per second, is given for a particle moving along a straight line.

(a) We are asked to find the displacement over the interval $1\leq t\leq 4$ .

Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.

$\int\limits^b_a {v(t)} \, dt$

$\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt$

$\int\limits^4_1 {\frac{1}{t^{\frac{1}{2}}} \, dt$

$\int\limits^4_1 t^{-\frac{1}{2}} \, dt$

Using power rule, we will get:

$\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1$

$\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1$

$\left[2t^{\frac{1}{2}}\right] ^4_1$

$2(4)^{\frac{1}{2}}-2(1)^{\frac{1}{2}}=2(2)-2=4-2=2$

Therefore, the total displacement on the interval $1\leq t\leq 4$ would be 2 feet.

(b). For distance we need to integrate the absolute value of the velocity function.

$\int\limits^b_a |{v(t)|} \, dt$

$\int\limits^4_1 |{\frac{1}{\sqrt{t}}}| \, dt$

Since square root is not defined for negative numbers, so our integral would be $\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt$ .

We already figured out that the value of $\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt$ is 2 feet, therefore, the total distance over the interval $1\leq t\leq 4$ would be 2 feet.

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3 years ago

000059.23 - 000044.18 =

Margarita [4]

Answer:

15.05

Step-by-step explanation:

Also, you don't need to add the zeros, they don't mean anything.

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3 years ago

How do you show three and three force of a number like

satela [25.4K]

Answer:

3 $\frac{3}{4}$

Hope this helps :)

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3 years ago

Diane uses 2 feet of ribbon to decorate each gift she is wrapping. She wraps 7 gifts. How much ribbon does she need?

lakkis [162]

14, because 2x7=14. Every gift box uses 2 feet on ribbon. There are 7 gift boxes, so she needs 2+2+2+2+2+2+2 length of ribbon.

5 0

4 years ago