So I think the answer to m<5 is 75 degrees
Answer:
y=3
Step-by-step explanation:
y + 3 = -y + 9
y + y = 9 - 3
2*y = 6
y = 6/2
y = 3
Y = a x² + b x + c
y = 0.0473809524 · 20² + 2.221428571 · 20 - 0.005952381 =
= 18.95236 + 44.42875 - 0.05952381 = 63.374978 ≈ 63.4
Answer: C ) 63.4 ft.
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

Answer:
Final amount of customers =30141.44
Step-by-step explanation:
Amount of customer remaining
A= p(1-r/n)^(nt)
P= initial amount of customers
R= rate but it's a negative rate
N= number of times
T= number of years
A= final amount of customers
A= p(1-r/n)^(nt)
A= 51200(1-0.038/14)^(14*14)
A= 51200(1-0.0027)^196
A= 51200(0.9973)^196
A= 51200(0.5887)
A= 30141.44