I need help with this math problem please

Mathematics

2 answers:

liraira [26]3 years ago

8 0

It’s D

have a great day!

photo attached below :)

nikdorinn [45]3 years ago

8 0

Answer:

option D

Step-by-step explanation:

$9x^2 + 6x - 17 = 0 , \ where \ a = 9 \ , \ b = 6 \ , c = - 17$

$x = \frac{ - b \ \pm \sqrt{b^2 - 4ac}}{2a} \\\\x = \frac{-6 \pm \sqrt{36 - (4 \times 9 \times -17)}}{2 \times 9}\\\\x = \frac{-6 \pm \sqrt{ 36 + 612}}{18}\\\\x = \frac{-6 \pm \sqrt{ 648}}{18}\\\\x = \frac{-6 \pm \sqrt{ 2^3 \times 3^4}}{18}\\\\x = \frac{-6 \pm \sqrt{2 \times 2^2 \times 3^ 4 }}{18}\\\\x = \frac{-6 \pm ( 2 \times 9 )\sqrt{ 2}}{18}\\\\x = \frac{-6 \pm 18\sqrt{2}}{18}\\\\x = \frac{-1 \pm 3 \sqrt{ 2}}{3}$

You might be interested in

HELP!! I'm not sure what goes in the blank.

natta225 [31]

Answer:

10 $sin^{2} ($ β $)$

Step-by-step explanation:

We can find this two ways, first by seeing in the step after it, cosines are canceled out. Since you already have 10 $sin^{2} ($ β $)$ on the next step, you can assume that (since only the cosines changed and the cosine next ot the blank was removed), the value is 10 $sin^{2} ($ β $)$ .

You can also use double angle formulas from the previous step:

(sin(2β) = 2 sin(β) cos(β))and find that:

5 sin (2β) sin(β) = 5 * (2 sin(β) cos(β)) sin(β)) = (10 sin(β) sin(β)) cos(β) =

10 $sin^{2} ($ β $)$ cos(β)

But since cos(β) is already present, we can see that the answer is 10 $sin^{2} ($ β $)$

4 0

2 years ago

What is the solution of 2x+2y=10 y=8x+5

Phantasy [73]

Search it up on the internet they should give you the answer

3 0

4 years ago