Ask question

Ask question

All categories

brilliants [131]

3 years ago

10

(y + 2)(y^2 - 2y + 3)

1 answer:

Olegator [25]3 years ago

3 0

Answer:

y^3 - y + 6

Step-by-step explanation:

I believe this is right

You might be interested in

How do you find 15% of a number

Mumz [18]

When you multiply a number by a percentage, you first convert the percent into a decimal.

You do this by moving the decimal point two places to the left and making the decimal point into % sign.

15% = 0.15

Then you multiply the decimal by the number you want to find the percentage of.

So, the answer to this question is <span>A. multiple the number by 0.15</span>

3 0

3 years ago

1.Consider the average speed of a runner who jogs around a track four times. The distance (400m) remains constant for each lap.

Elenna [48]

question one is C)

question two is D)

question three is D)

question four is B)

question five is B)

question six is B)

question seven is B)

question eaghit is C)

hope ths helps pleas leave comments to let me know if I got anything wrong.

4 0

3 years ago

Read 2 more answers

A direct variation function contains the points (2, 14) and (4, 28). Which equation represents the function?

IgorC [24]

Direct variation mean x =ky so y = x/k

(2,14) mean y = kx so 14 = k*2 so 14 = 7*2 so 14 = 14
(4,28) mean y = kx so 28 = k*4 so 28 = 7*4 so 28 = 28

from these result that the 3rd choice is right sure

6 0

3 years ago

Read 2 more answers

Evgesh-ka [11]

9514 1404 393

Answer:

Moana: 68 seed packets
Afa: 27 calendars

Step-by-step explanation:

Let c represent the number of calendars sold. Then 95-c is the number of seed packets sold. The total revenue is ...

0.65(95-c) +1.50c = 84.70

0.85c = 22.95 . . . . . . . . . . . . subtract 61.75

c = 27

95 -c = 68

Moana sold 68 seed packets; Afa sold 27 calendars.

5 0

3 years ago

Laura and Philip each fire one shot at a target. Laura has probability 0.4 of hitting the target, and Philip has probability 0.1

Pepsi [2]

Answer:

(i) 0.46, (ii)0.42, and (iii)0.143

Step-by-step explanation:

Let $p$ be the probability of hitting the target and $q$ be the probability of missing the target by Laura.

Given that $p=0.4\;\cdots (1)$

As Laura either hit or miss the target, so $p+q=1$ .

$\Rightarrow q=1-p=0.6 \; \cdots (2)$

Again, let $r$ be the probability of hitting the target and $s$ be the probability of missing the target by Philip.

Here, $r=0.1\;\cdots (3)$

Similarly, $\Rightarrow s=1-r=0.9\;\cdots (4)$

(i)The probability that the target is hit means that the target is not missed by both, either of one or both hit the target.

=1-(probability of missing the target by both)

=1- $qr$ [from equation (2) and (4) ]

= $1-0.6\times 0.9$

= $1-0.54$

=0.46

(ii) The probability that the target is hit by exactly one shot means either of one hit the target.

=Hit by Laura and missed by Philip or hit by Philip and missed by Laura

$=0.4\times 0.9+0.1\times 0.6$ [from equations (1),(4) and (3),(2)]

$=0.36+0.06$

=0.42

(iii)Given that the target was hit by exactly one shot, so, the given probability is 0.42 [from (ii) part]

No, the probability that the target was hit by Philip = probability of hitting the target by Philip and missing the target by Laura

$=0.1\times 0.6$ [from equations (3) and (2)]

=0.06

So, the probability of hitting the target by Philip

$=\frac {0.06}{0.42}$

$=\frac {1}{7}$

$=0.143$ (approx)

6 0

3 years ago