L= 3w
Perimeter form = 2(l+w)
2(3w + w) = 112
6w + 2w = 112
8w = 112
w= 14
The greatest possible value for w is 14
Hope this helps!
66 minutes or 1 hour and 6 minutes
First divide 6 into 44 then multiply that number by 9 (:
Answer:
The answer is D
Step-by-step explanation:
took the test<//3
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
2 modes are radian and degree, should be set on radian for most classes, and you change by pressing mode