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3 years ago

Example 24 In a school there are 20 teachers who teach mathematics or physil

Mathematics

2 answers:

Otrada [13]3 years ago

5 0

The number of teachers who teach physics n(P) = 12

Step-by-step explanation:

Trava [24]3 years ago

3 0

Answer:

The number of teachers who teach physics n(P) = 12

Step-by-step explanation:

Step(i):-

Given that the number of teachers who teach mathematics or physics

n(MUP) = 20

Given that the number of teachers who teach mathematics

n(M) = 12

Given that the number of teachers who teach both mathematics and physics

n(M∩P) = 4

Step(ii):-

By using n(A∪B) = n(A) + n(B) - n(A∩B)

n(M∪P) = n(M) +n(P) - n(M∩P)

20 = 12 + n(P) - 4

20 -12 +4 = n(P)

n(P) = 12

Final answer:-

The number of teachers who teach physics n(P) = 12

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Answer:

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Step-by-step explanation:

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2 years ago

Miranda earned $c for working 8 hours. Write an expression to show how much Miranda earned for each hour she worked.

BabaBlast [244]

$c/8
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3 years ago

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morpeh [17]

Answer:

7.7 km

Explanation:

Use cosine rule as here given two sides and one angle.

Cosine rule states:

a² = b² + c² - 2bc cos(A)

While solving, treat a = 7.5 km as to that opposite angle is given of 68°

then b = missing side, c = 5.2 km, A = 68°

Applying rule:

7.5² = b² + 5.2² - 2(b)(5.2) cos(68)

56.25 = b² + 27.04 - 3.8959b

56.25 - 27.04 = b² - 3.8959b

b² - 3.8959b = 29.21

b² - 3.8959b - 29.21 = 0

apply quadratic equation, Here [a = 1, b = - 3.8959, c = -29.21]

$\sf b = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad\:when \:\ ax^2 + bx + c = 0$

$\sf b = \dfrac{ -(-3.8959) \pm \sqrt{(-3.8959)^2 - 4(1)(-29.21)}}{2(1)}$

$\sf b = 7.69 291 \quad or \quad b = -3.797$

$\sf b = 7.7 \quad (rounded \ to \ nearest \ tenth)$

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7 0

1 year ago

Read 2 more answers

2x+5=10 someone help me

TiliK225 [7]

Answer:

2x=5 x=2.5

Step-by-step explanation:

2x+5=10

2x=10-5

2x=5

x=2.5

5 0

3 years ago

Read 2 more answers