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Viktor [21]
3 years ago
8

Which of these shapes have the same perimeter

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

A) B and C

Step-by-step explanation:

To find the perimeter, add up the lengths of all the sides.

For shape A: 16+16+1+1= 34

For shape B: 8+8+2+2= 20

For shape C: 5+5+5+5= 20

Shapes B and C both have a perimeter of 20. The answer is A, B and C.

I hope this helps!

___________________________________________________________

The other answer is not correct because they are finding the area of the rectangles.

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Will someone please answer this?
AfilCa [17]
Ok so you would find the area of all of the shapes and then add it together. to find the area of the square you would multiply 8 by 8 to get 64. Then you would go on to finding the area of the four triangles which can be found by multiplying the base times the height to get 48. after you do this you would divide 48 by two to get 24 which is your area for the triangles. since there are four triangles you would multiply 24 by 4 to get 96. Finally to get the surface area you add 96 with 64 to get your surface area which is 160 in^2
4 0
3 years ago
What is .00000786 in scientific notation
Bas_tet [7]

Sorry that I don't have the answer. Hope this helps!

Remember that any whole number can be written with a decimal point. For example: 2,890,000,000 = 2,890,000,000.0

Now, move the decimal place until you have a number between 1 and 10. If you keep moving the decimal point to the left in 2,890,000,000 you will get 2.89.

Next, count how many places you moved the decimal point. You had to move it 9 places to the left to change 2,890,000,000 to 2.89. You can show that you moved it 9 places to the left by noting that the number should be multiplied by 109

5 0
3 years ago
Read 2 more answers
I need help with #10 please! Thanks!
Anastasy [175]
√27 can be simplified. First we split it into √9√3 because 9*3=27. Now the √9 becomes 3. We can multiply this 3 with the 3 in the beginning of the problem to get 9√3 as the final answer

Hope this helps
7 0
4 years ago
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 72 type K batteries and a sample of 49
rewona [7]

Answer:

Given:

For battery k(sample 1):

Sample size, n = 75

Sample mean, X' = 9.41

Standard deviation = 0.723

Mean u1 =???

For battery Q(sample 2):

Sample size, n = 49

Sample mean, X' = 9.69

Standard deviation = 0.257

Mean u2 =???

Significance level = 0.05

1) The null and alternative hypotheses, will be given as:

H0 : u1 - u2 = 0

H1 : u1 - u2 ≠ 0

2) This is a two tailed test.

For the test statistic, we have :

Z_o = \frac{X'_1 - X'_2}{\sqrt{\frac{(\sigma_1)^2}{n_1} + \frac{(\sigma_2)^2}{n_2}}}

= \frac{9.41 - 9.69}{\sqrt{\frac{(0.723)^2}{75} + \frac{(0.257)^2}{49}}} = - 3.018

≈ 3.02

The Zo = - 3.02

3) For the p value, using excel, we have:

2 * P(Z > (-3.018))

= 2 * NORMDIST (-3.018, 0, 1, true)

= 0.00254

For critical value:

Zcritical = Za/2 = 0.05/2

Zcritical = 0.025

We have alternative hypothesis,

H1 : u1 - u2 ≠ 0.

Therefore we reject null hypothesis H0 if Zo > Zcritical

4) We reject null hypothesis H0 if Zo > Zcritical. At 0.05 level of significance, there is not enough evidence to conclude that mean u1 and mean u2 are different.

4 0
3 years ago
Can someone help me?
jekas [21]
The answer is three
6 0
3 years ago
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