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Alborosie
3 years ago
9

What is the exact value of Tangent (StartFraction 9 pi Over 8 EndFraction)?

Mathematics
2 answers:
malfutka [58]3 years ago
8 0

Answer:

B on edge

Step-by-step explanation:

Alexandra [31]3 years ago
4 0

Answer:

B

Step-by-step explanation:

edg 2021

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Roger can type 1530 words in 1/2 hour. How many words can he type per<br> minute?<br> PLS HELP ME
Lera25 [3.4K]

Answer:

25.5

Step-by-step explanation:

1530 divided by 60 is 25.5 and 25.5 multiplied by 60 is 1530.

6 0
2 years ago
YOU HAVE A SWELLING INJURY. DO YOU USE….<br> Heat or ice?
blagie [28]

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Ice would be the correct answer.

7 0
3 years ago
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A 30 minute TV program consist of three commercials, each 2 1/2 minutes long, and four equal length entertainment segments. How
maksim [4K]
Each one would be 5 minutes because 2 1/2 Times 4 = 10 minutes. You would have 20 minutes remaining so divide 20 by how many segments there are, which is 4 to get 5
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4 years ago
Sally has a part time job mowing lawns so she can save money for a new car. She charges $5 per hour. What numbers make sense for
Ira Lisetskai [31]

Answer:

Independent: Amount of hours she works

Dependent: Amount of money she makes

Step-by-step explanation:

The independent variable is the part of the equation that changes. In this case the only thing that changes is how long she works, the amount of money she charges and what she is doing does not change.

The dependent variable is what you measure in the equation. In this case, the amount of money she makes depends on the amount of time she works.

5 0
3 years ago
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Consider an ionic compound, MX, composed of generic metal M and generic, gaseous halogen X.
Art [367]

As the given values are

<span>ΔHf° = –423 kJ/mol
</span>ΔHsub = 119 kJ/mol
IE = 469 kJ/mol
ΔHEA = –301 kJ/mol
BE = 161 kJ/mol

The lattice energy of the compound can be determined by applying formula

U = <span>ΔHf° - </span>ΔHsub - BE - IE - ΔHEA
by putting values
U = -423 - 119 - 161 - 469 - (-301)
solving further
U = -871 kJ/mol

so the lattice energy is 871 kJ/mol
hope it helps
8 0
3 years ago
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