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3 years ago

Which statement correctly compares the parking rates for each lot?

Mathematics

1 answer:

cupoosta [38]3 years ago

3 0

Answer: O Lot B costs $0.01 more

Step-by-step explanation: I think it’s O Lot B costs $0.01 more per hour than Lot A

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The equation y minus two-thirds = negative 2 (x minus one-fourth) is written in point-slope form. What is the equation in slope-

Lena [83]

Answer:

(B) $y=-2x+ \dfrac{7}{6}$

Step-by-step explanation:

Given the point-slope form of the equation of a line below:

$y-\dfrac{2}{3}=-2\left(x- \dfrac{1}{4}\right)$

We are required to write it in the slope-intercept form, y=mx+c.

$y-\dfrac{2}{3}=-2\left(x- \dfrac{1}{4}\right)\\\\y-\dfrac{2}{3}=-2x+ \dfrac{2}{4}\\\\y=-2x+ \dfrac{2}{4}+\dfrac{2}{3}\\\\y=-2x+ \dfrac{7}{6}$

The slope intercept form is:

$y=-2x+ \dfrac{7}{6}$

<u>The correct option is B.</u>

5 0

3 years ago

Read 2 more answers

Rewrite the equation below so that it does not have fractions.

Vlad1618 [11]

Answer:

9x=38

Step-by-step explanation:

8 0

2 years ago

Tanisha was asked to write an example of a linear relationship she wrote this my dog sitting service charges an initial $8.00 fe

stich3 [128]

1. 15.50
2. 23.00
3. 30.50
4. 38.00

5 0

3 years ago

Need help ASAP

joja [24]

Part (1) : The solution is $729$

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

Explanation:

Part (1): The expression is $3^{2} \cdot3^{4}$

Applying the exponent rule, $a^{b} \cdot a^{c}=a^{b+c}$ , we get,

$3^{2} \cdot 3^{4}=3^{2+4}$

Adding the exponent, we get,

$3^{2} \cdot3^{4}=3^6=729$

Thus, the simplified value of the expression is $729$

Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\left(2 x^{2}\right)^{-4}=\frac{1}{\left(2 x^{2}\right)^{4}}$

Simplifying the expression, we have,

$\frac{1}{2^4x^8}$

Thus, we have,

$\frac{1}{16 x^{8}}$

Thus, the value of the expression is $\frac{1}{16 x^{8}}$

Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

Applying the exponent rule, $\frac{x^{a}}{x^{b}}=x^{a-b}$ , we have,

$\frac{2x^{4-2}y^{-4+3}z^{-3-4}}{3}$

Adding the powers, we get,

$\frac{2x^{2}y^{-1}z^{-7}}{3}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

8 0

3 years ago

CAN SOMEONE HELP ME WITH THISSSS

Semmy [17]

Answer:

no i cannot

Step-by-step explanation:

4 0

2 years ago