PLEASE HELP ASAP I NEED THIS HW IN A HOUR! I MARK BRAINLIEST! Which data set could be represented by the box plot shown below?
1 answer:
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The question is incomplete. Here is the complete question.
To set up a game of billiards, the first player moves the balls contained within a triangular rack as shown. What happens to the distance between each billiard during this rigid transformation?
A. The distance remains constant throughout the transformation.
B. The distance decreases at the start and increases after all motion stops.
C. The distance stays the same at the start but decreasesexactly when motion ends.
D. The distance increases at the start and then decreases as the rack gets further from the player.
Answer: A. The distance remains constant throughout the transformation.
Step-by-step explanation: In a <u>rigid</u> <u>motion</u>, all moving points in the plane are moving in way such tha:
1) relative distance between them stays the same and
2) relative position of the points stays the same
There are four types of rigid motions: translation, rotation, reflexion and glide reflection.
<u>Translation</u>: every point or object is moved by the same amount and in the same direction;
<u>Rotation</u>: the object rotates by the same amount around a fixed point;
<u>Reflexion</u>: the object exchange points from one side of a line with points on the other side of the line at the same distance from the line;
<u>Glide</u> <u>Reflection</u>: is a mirror reflection followed by a translation parallel to the mirror.
In the game of billiards, because all the balls are inside the triangular rack, the distance, and also the position, between them stays the same, limited by the rack. Since they are moving by the same amount in the same direction, the rigid transformation is a translation.
Therefore, the distance of the balls in the triangular rack remains constant throughout the transformation.
<h3>Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that
Answer:
The farthest point is the Challenger Deep
Step-by-step explanation:
Given
Solving (a): The sea level
Both elevations had signs in front of them.
The sea level is the point at the neutral level, neither positive nor negative.
Hence:
Solving (b): Farthest Point.
The farthest point is the one with the highest magnitude.
Comparing
to
-35,797 ft has the highest magnitude.
Hence:
<em>The farthest point is the Challenger Deep</em>