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Marizza181 [45]
3 years ago
6

Q: A is 8km due north of phone mast B. C is 9.5km due west of phone mast B. Calculate the distance AC

Mathematics
1 answer:
Evgen [1.6K]3 years ago
7 0

Answer:

AC = 12.4 km (nearest tenth)

Step-by-step explanation:

AC can be calculated by using Pythagorean Theorem.

Thus:

AC² = AB² + BC²

Plug in the values

AC² = 8² + 9.5²

AC + √{154.25)

AC = 12.4 km (nearest tenth)

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podryga [215]

Answer:

Matrix transformation = \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right].

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-5\\-2\end{array}\right]= (5,-2)

Q'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-6\\-3\end{array}\right]= (6,-3)

R'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-2\\-3\end{array}\right]= (2,-3)

3 0
3 years ago
(2.1 X 10^9) - (9.7 x 10^7) =<br> What does this equal
andriy [413]
I think 2003000000 is the answer
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3 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
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c = 0.10m + 30 represents the situation.

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Help please! 10 points!
IgorC [24]

Answer:

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Triangles have same angles. This means that they are proportion.

50/27 = 40/x

when you cross multiply to solve x, 50x = 1080

so x = 21.6

If you have to nearest whole number, it will be 22

7 0
3 years ago
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