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3 years ago

Q: A is 8km due north of phone mast B. C is 9.5km due west of phone mast B. Calculate the distance AC

Mathematics

1 answer:

Evgen [1.6K]3 years ago

7 0

Answer:

AC = 12.4 km (nearest tenth)

Step-by-step explanation:

AC can be calculated by using Pythagorean Theorem.

Thus:

AC² = AB² + BC²

Plug in the values

AC² = 8² + 9.5²

AC + √{154.25)

AC = 12.4 km (nearest tenth)

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What is the maximum value of P = 24x + 30y, given the constraints on x and y listed below? x+y (less than or equal to) 5 x-y (gr

valentina_108 [34]

Answer:

Step-by-step explanation:

We have to first find the vertices of the feasible region before we can determine the max value of P(x, y). We will graph all 4 of those inequalities in a coordinate plane and when we do that we find that the region of feasibility is bordered by the vertices (0, 0), (0, 1), (2, 3), and (5, 0). Filling each x and y value into our function will give us the max value of that function.

Obviously, when we sub in (0, 0). we get that P(x, y) = 0.

When we sub in (0, 1) we get 24(0) + 30(1) = 30.

When we sub in (2, 3) we get 24(2) + 30(3) = 138.

When we sub in (5, 0) we get 24(5) + 30(0) = 120.

Obviously, the vertex of (2, 3) maximized our function for a value of 138.

6 0

3 years ago

2. The mean birth weight of a full term boy born in the US is 7.7 lbs, with standard deviation of 1.1 lbs. A. Find the probabili

Fed [463]

Answer:

The value is $P( X < 7 ) =0.26226$

The value is $P( X < 7 ) = 0.00073$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 7.7 lbs$

The standard deviation is $\sigma = 1.1 \ lbs$

The sample size is n = 25

Generally the probability that a boy born full term in the US weighs less than 7 lbs is mathematically represented as

$P( X < 7 ) = P( \frac{X - \mu }{\sigma} < \frac{7 - 7.7 }{1.1 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

=> $P( X < 7 ) = P(Z$

From the z table the area under the normal curve to the left corresponding to -0.6364 is

$P(Z$

=> $P( X < 7 ) =0.26226$

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 1.1 }{\sqrt{25} }$

=> $\sigma_{x} = 0.22$

Generally the probability that the average weight of 25 baby boys born in a particular hospital have an average weight less than 7 lbs is mathematically represented as

$P( \= X < 7 ) = P( \frac{\= X - \mu }{\sigma_{x}} < \frac{7 - 7.7 }{ 0.22 } )$