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7nadin3 [17]
3 years ago
7

Consider the spreading of a rumor through a company of 1000 employees, allworking in the same building.We assume that the spread

ing of a rumor is similar to the spreading of a contagious disease (see Example 3, Section 1.2) in that the number of people hearing the rumor each day is proportional to the product of the number who have heard the rumor previously and the number who have not heard the rumor. This is given by
rn+1 = rn + 1000krn(1000 ? rn)
where k is a parameter that depends on how fast the rumor spreads and n is the number of days. Assume k = 0.001 and further assume that four people initially have heard rumor. How soon will all 1000 employees have heard the rumor?
Mathematics
1 answer:
natima [27]3 years ago
5 0

Answer:

On the 12th day, the rumor would have has to all the 1000 employees

Step-by-step explanation:

Given the data in the question;

so, lets consider the rumor spreading thorough the company of 1000 employee;

the given model is; r_{n+1} = r_{n} + 1000kr_{n} ( 1000 - r_{n} )

where k is the parameter that depends on how fast the rumor spreads, n is the number of days.

now, lets assume k = 0.0001, lets also assume r₀ = 4

so to find how soon all 1000 employees  will have heard the rumor  ;

let n be;

then r1 will be;

r1 = r₀ + ( 0.001)r₀(1000-r₀ )

so

r1 = 4 + ( 0.001) × 4× (1000 - 4 )

r1 = 7.984

r2 will be;

r2 = r1 + ( 0.001)r1(1000-r1 )

r2 =  7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )

r2 = 15.904255744

   

r3  will be;

r3 = r2 + ( 0.001)r2(1000-r2 )  

r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )

r3 = 31.555566137

Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.

we will have;

n        rₙ

0        4

1        7.984

2       15.904255744

3       31.555566137

4       62.1153785

5       120.372437

6       226.25535

7       401.319217

8       641.58132

9       871.53605

10     983.497013

11      999.727651

12     999.999926

Therefore, On the 12th day, the rumor would have has to all the 1000 employees

 

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sergey [27]
These are two questions and two answers.

1) Problem 17.

(i) Determine whether T is continuous at 6061.

For that  you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.

a) T(x) = 0.10x if 0 < x ≤ 6061

T (6061) = 0.10(6061) = 606.1

b) limit of Tx when x → 6061.

By the left the limit is the same value of T(x) calculated above.

By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)

⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10

Since both limits and the value of the function are the same, T is continuous at 6061.

(ii) Determine whether T is continuous at 32,473.

Same procedure.

a) Value at 32,473

T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26

b) Limit of T(x) when x → 32,473 from the right

Limit = 5360.26 + 0.26(x - 32,473) = 5360.26

Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.

(iii) If  T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.

2) Problem 18.

a) Statement Sk

You just need to replace n for k:

Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2

b) Statement S (k+1)

Replace

S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2

Simplification:

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Do the operations on the left side and  you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.

With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.

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